How do you solve $- \frac{1}{2} x + 1 = - x + 8$ $-1/2x+1=-x+8$ ?

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Answer 1 · 2016-09-17T17:32:03

$x = 14$ $x=14$

Given $- \frac{1}{2} x + 1 = - x + 8$ $-1/2x+1=-x+8$

$- \frac{1}{2} x + 1 + x = - x + 8 + x$ $-1/2x+1+x=-x+8+x" " " "$ Add x on both sides

$x - \frac{1}{2} x + 1 = 8$ $x-1/2x+1=8" " "$ combine like terms

$x - \frac{1}{2} x + 1 - 1 = 8 - 1$ $x-1/2x+1-1=8-1" " "$ Subtract 1 on both sides

$\frac{1}{2} x = 7$ $1/2x=7" " " "$ combine like terms

$x = 14$ $x=14" " " "$ Multiply both sides by 2

God bless....I hope the explanation is useful.

How do you solve −12x+1=−x+8-1/2x+1=-x+8?