How do you solve $2 - 5 (x + 1) \geq 4 (x - 1) - 26$ $2- 5( x + 1) \geq 4( x - 1) - 26$ ?

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Answer 1 · 2016-09-25T02:31:19

$x \leq - 3$ $x <= -3$

We need to solve the equation by isolating the $x$ $x$ variables.

First, we distribute $- 5$ $-5$ and $4$ $4$ into the parenthesis. We get:

$2 - 5 x - 1 \geq 4 x - 1 - 26$ $2 - 5x-1 >= 4x-1 -26$ (multiplied $- 5$ $-5$ by x and $1$ $1$ and multiplied $4$ $4$ by x and $- 1$ $-1$ )

Then we isolate the $x$ $x$ values.

$- 5 x - 4 x \geq - 26 + 1 - 2$ $-5x -4x >= -26 +1 -2$

Now we combine like terms

$- 9 x \geq - 27$ $-9x >= -27$

Now to isolate the x, we divide both sides by $9$ $9$ . Whenever we divide or multiply both sides with a negative number we flip the inequality sign.

$x \leq 3$ $x <= 3$

How do you solve 2−5(x+1)≥4(x−1)−262- 5( x + 1) \geq 4( x - 1) - 26?