How do you solve #16- ( 4+ 3) \cdot 2#?

1 Answer
Jim G.
Sep 29, 2016

2

Explanation:

When evaluating expressions with #color(blue)"mixed operations"# there is a particular order that must be followed.

Follow the order as set out in the acronym PEMDAS.

#16-(4+3)xx2larr" brackets first"#

#rArr16-7xx2larr" next multiplication"#

#rArr16-14larr" finally subtraction"#

#=2#

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