How do you write the partial fraction decomposition of the rational expression (x^3 - 5x + 2) / (x^2 - 8x + 15)?

1 Answer
Oct 5, 2016

(x^3 - 5x + 3)/(x² - 8x + 15) = x + 8 + 45/2(1/(x - 3)) + 43/2(1/(x - 5))

Explanation:

We need to do the division first. I am going to use long division, because I prefer it over synthetic:

.............................x + 8
............................__
x² - 8x + 15)x^3 + 0x^2 - 5x + 3
........................-x^3 + 8x² -15x
.......................................8x²-20x + 3
...................................-8x² + 64x - 120
.....................................................44x - 117

Check:

(x + 8)(x² - 8x + 15) + 44x - 117 =

x³ - 8x² + 15x + 8x² -64x + 120 + 44x - 117 =

x³ - 5x + 3 This checks

(x^3 - 5x + 3)/(x² - 8x + 15) = x + 8 + (44x - 177)/(x² - 8x + 15)

Now we do the decomposition on the remainder:

(44x - 177)/(x² - 8x + 15) = A/(x - 3) + B/(x - 5)

44x - 177 = A(x - 5) + B(x - 3)

Let x = 3:

44(3) - 177 = A(3 - 5) + B(3 - 3)

-45 = -2A

A = 45/2

Let x = 5:

44(5) - 177 = A(5 - 5) + B(5 - 3)

43 = 2B

B = 43/2

(x^3 - 5x + 3)/(x² - 8x + 15) = x + 8 + 45/2(1/(x - 3)) + 43/2(1/(x - 5))