How do you simplify $\frac{x - 5 y}{x + y} + \frac{x + 7 y}{x + y}$ $\frac{x-5y}{x+y}+\frac{x+7y}{x+y}$ ?

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Answer 1 · 2016-10-08T16:18:45

$\frac{x - 5 y}{x + y} + \frac{x + 7 y}{x + y} = 2$ $(x - 5y)/(x + y) + (x + 7y)/(x + y) = 2$

Because the denominators are the same, one can just add the numerators over the common denominator:

$\frac{x - 5 y + x + 7 y}{x + y} = \frac{2 x + 2 y}{x + y}$ $(x - 5y + x + 7y)/(x + y) = (2x + 2y)/(x + y)$

Factor out $(x + y)$ $(x + y)$ from the numerator:

$\frac{2 (x + y)}{(x + y)} = 2$ $(2(x + y))/((x + y)) = 2$

The simplest form is:

$\frac{x - 5 y}{x + y} + \frac{x + 7 y}{x + y} = 2$ $(x - 5y)/(x + y) + (x + 7y)/(x + y) = 2$

How do you simplify \frac{x-5y}{x+y}+\frac{x+7y}{x+y}x−5yx+y+x+7yx+y\frac{x-5y}{x+y}+\frac{x+7y}{x+y}?