How do you solve #0. 2 ( b - 1 2 ) = 0 . 4 b#?

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Answer 1 · 2016-10-12T05:54:28

#-12#

First you should distribute #0.2#:

#0.2b-12(0.2)=0.4b#

that yields:

#0.2b-2.4=0.4b#

Subtract #0.2b# from both sides:

#-2.4=0.4b-0.2b#

#-2.4=0.2b#

#-2.4/0.2=b#

#b=-12#

Good Luck