How do you find (d^2y)/(dx^2) for 5=x^2-2y^2?
3 Answers
Oct 14, 2016
Deleted, because it was incorrect
I get
Explanation:
= ((1)(2y)-x(2(dy/dx)))/(2y)^2
= (2y-2x(x/(2y)))/(4y^2)
= (y-x(x/(2y)))/(2y^2)
= (y-x(x/(2y)))/(2y^2) * (2y)/(2y)
= (2y^2-x^2)/(4y^3
We started with
Oct 14, 2016