How do you solve #\frac { 6x - 8} { 7} = - 1#?

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Answer 1 · 2016-10-18T20:57:52

the answer is #x = 1/6#

First you multiply both sides of the equation by 7 to clear the fraction so

#(7xx(6x-8))/7 = (7)(-1)#
which gives

#6x-8 = -7#

then you add #8# to both sides to begin isolating the x-value

#6x = -7+8# which gives

#6x = 1#

then divide by #6# to totally isolate the x

#(6x)/6 = 1/6#

or

#x = 1/6#