How do you combine $(4 x + 4 x^{2}) - (7 x^{2} + x)$ $(4x + 4x ^ { 2} ) - ( 7x ^ { 2} + x )$ ?

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Answer 1 · 2016-10-20T08:16:00

The sum is $3 x - 3 x^{2}$ $3x-3x^2$

Check down for some more :)

If by combining, you mean to add them then,

$(4 x + 4 x^{2}) - (7 x^{2} + x) = 4 x + 4 x^{2} - 7 x^{2} - x = 3 x - 3 x^{2}$ $(4x+4x^2)-(7x^2+x)=4x+4x^2-7x^2-x=3x-3x^2$

If you mean to factorize then solve, all you have to do is to equal that to $0$ $0$

$3 x - 3 x^{2} = 3 x (1 - x)$ $3x-3x^2=3x(1-x)$ That's the factorization

Solving for $x \Rightarrow 3 x (1 - x) = 0$ $x=>3x(1-x)=0$

$\Rightarrow 3 x = 0$ $=>3x=0$ and $1 - x = 0$ $1-x=0$

$\Rightarrow x = 0$ $=>x=0$ and $x = 1$ $x=1$

Hope this helps :)

How do you combine (4x+4x2)−(7x2+x)(4x + 4x ^ { 2} ) - ( 7x ^ { 2} + x )?