How do you solve $log_4 5 - log_4 (-4x)=1$ ?

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Answer 1 · 2016-10-20T16:38:16

$x = - 5/16$

$log_4 5 - log_4 (-4x) = 1$

$log_4 5 - log_4 (-4x) = log_4 4$

$log_4 (5/(-4x)) = log_4 4$

$(5/(-4x)) = 4$

$x = -5/16$

How do you solve log_4 5 - log_4 (-4x)=1log_4 5 - log_4 (-4x)=1?