Common Logs
Key Questions
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There are 2 ways.
The math way is to understand how to convert bases:
log a=(ln a)/(ln 10) The second way is to use the "CATALOG" button, "L", scroll down to "log" and press enter.
Here is an example of
log 50 :=(ln 50)/ln(10)
~~1.69897 -
Answer:
See the explanation.
Explanation:
If you have technology available for the logarithm in some other base (
e or2 ), uselog_10 n = log_b n / log_b 10 (whereb = e " or "2 )With paper and pencil, I don't know a good series for
log_10 n .Probably the simplest way is to use a series for
ln n and either a series or memorization forln 10 ~~ 2.302585093 For
ln n , letx=n-1 and use:ln n = ln (1 + x) = x − x^2/2 + x^3/3- x^4/4+x^5/5- * * * After you find
ln n , use division to getlog_10 n ~~ ln n / 2.302585093 -
Answer:
The inverse of the function
f(x) = 10^x Explanation:
The function:
f(x) = 10^x is a continuous, monotonically increasing function from
(-oo, oo) onto(0, oo) graph{10^x [-2.664, 2.338, -2, 12.16]}
Its inverse is the common logarithm:
f^(-1)(y) = log_10(y) which as a result is a continuous, monotonically increasing function from
(0, oo) onto(-oo, oo) .graph{log x [-1, 12.203, -1.3, 1.3]}
Note that the exponential function satisfies:
10^a * 10^b = 10^(a+b) Hence its inverse, the common logarithm satisfies:
log_10 xy = log_10 x + log_10 y