How do you calculate $log_2 4 - log_4 2$ ?

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Answer 1 · 2016-08-01T09:05:57

$log_(2)4-log_(4)2$ $=$ $2-1/2$ $=$ $3/2$

When I write $log_(a)b$ $=$ $c$ , in effect I ask to what power do I raise the base $a$ to get $b$ .

By this definition, if $log_(a)b$ $=$ $c$ , then $a^(c)=b$ .

Typically we use $"logs"$ to the base $10$ or the base $e$ .

Can you tell me what is $log_(10)100+log_(10)1000$ $?$

How do you calculate log_2 4 - log_4 2log_2 4 - log_4 2?