How do you expand $log ([sqrt(x+1)]/(x^2+1))$ ?

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Answer 1 · 2016-03-22T17:25:39

$log ((sqrt(x+1))/(x^2 +1))$ $=1/2 log(x+1)-log(x^2+1)$

$log ((sqrt(x+1))/(x^2 +1))$

$=logsqrt(x+1) - log (x^2+1)$ -> use property $log_b(x/y)=log_bx-log_by$

$=log(x+1)^(1/2) -log(x^2+1)$

$=1/2 log(x+1)-log(x^2+1)$

How do you expand log ([sqrt(x+1)]/(x^2+1))log ([sqrt(x+1)]/(x^2+1))?