Question

How do you condense `2log63 + 5log62 - 3log62`?

Answer 1

`=2(log(3906)`

Explanation:

`2log63+5log62-3log62=2log63+(5-2)log62=2log63+2log62`
`=2(log(63)+log(62))`
`=2(log(63xx62)` {using formula `logm +logn=log(mxxn)`)
`=2(log(3906)`