How do you condense $2log63 + 5log62 - 3log62$ ?

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Answer 1 · 2016-04-29T13:00:51

$=2(log(3906)$

$2log63+5log62-3log62=2log63+(5-2)log62=2log63+2log62$
$=2(log(63)+log(62))$
$=2(log(63xx62)$ {using formula $logm +logn=log(mxxn)$ )
$=2(log(3906)$

How do you condense 2log63 + 5log62 - 3log62 2log63 + 5log62 - 3log62 ?