How do you calculate $log_5 (1/125)$ ?

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Answer 1 · 2016-04-14T09:29:17

$log_5(1/125)=-3$

As $1/125=1/5^3=5^(-3)$

$log_5(1/125)=log_5(5^(-3))=-3log_5(5)=-3*1=-3$

How do you calculate log_5 (1/125) log_5 (1/125) ?