How do you calculate ${log}_{2} (2)$ $Log_2(2)$ ?

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Answer 1 · 2016-07-19T12:18:15

${log}_{2} (2) = 1$ $log_2(2)=1$

An expression in exponential form $a^{n} = b$ $a^n=b$ is written as ${log}_{a} b = n$ $log_ab=n$ .

Now $a^{1} = a$ $a^1=a$ for all $a$ $a$ , hence ${log}_{a} (a) = 1$ $log_a(a)=1$ . Hence,

${log}_{2} (2) = 1$ $log_2(2)=1$ as $2^{1} = 2$ $2^1=2$

How do you calculate log2(2)Log_2(2)?