Question

If log base 10 (2) = 0.301 & log base 10 (3) = 0.477, what does log base 10 (15) =?

Answer 1

I found: `1.176`

Explanation:

We can write it as:
`log_(10)(15)=log_(10)(30/2)`
using the property of logs of a fraction we get:
`log_(10)(30/2)=log_(10)(30)-log_(10)(2)=`
and:
`=log_(10)(10*3)-log_(10)(2)=`
we use the property of the log of a product to get:
`log_(10)(10)+log_(10)(3)-log_(10)(2)=`
`=1+0.477-0.301=1.176`