How do you simplify $log_2 14 - log_2 7$ ?

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Answer 1 · 2016-05-14T14:21:16

$log_2(14) - log_2(7) = 1$

Using the log rule $log_x(a) – log_x(b) = log_x(a/b)$

Rewrite the equation as:

$log_2(14/7)$ = $log_2(2)$

Use the log rule:

$log_x(x)$ = 1

Therefore $log_2(2)$ = 1

So $log_2(14) - log_2(7) = 1$

How do you simplify log_2 14 - log_2 7log_2 14 - log_2 7?