How do you condense $2ln8+5ln(z-4)$ ?

Question

3255 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-11T05:28:33

$ln(8^2(z-4)^5)$

We have:

$2ln8+5ln(z-4)$

We can use the rule that $xlny=lny^x$ to rewrite this:

$ln8^2+ln(z-4)^5$

We can then use the rule that $lnA + lnB=ln(AB)$ to rewrite:

$ln(8^2(z-4)^5)$

How do you condense 2ln8+5ln(z-4)2ln8+5ln(z-4)?