How do you evaluate $log 0.003$ $log0.003$ ?

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Answer 1 · 2016-12-18T06:16:03

$¯ 3 .4771$ $bar(3).4771$ or $- 2.5229$ $-2.5229$

$log 0.003$ $log0.003$

= $log (\frac{3}{1000})$ $log(3/1000)$

= $log 3 - log 1000$ $log3-log1000$

= $log 3 - {log 10}^{3}$ $log3-log10^3$

= $log 3 - 3 log 10$ $log3-3log10$

= $0.4771 - 3$ $0.4771-3$

= $¯ 3 .4771$ $bar(3).4771$ or $- 2.5229$ $-2.5229$

Note that in $¯ 3 .4771$ $bar(3).4771$ while characteristic $3$ $3$ is negative, mantissa is positive and is $0.4771$ $0.4771$

How do you evaluate log0.003log0.003log0.003?