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How do you condense #2log3 +3log2 - log6#?

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1 Answer

Konstantinos Michailidis

Feb 27, 2016

It is #log12#

Explanation:

It is

#2log3 +3log2 - log6=log3^2+log2^3-log6= log(3^2*2^3)-log6=log72-log6=log(72/6)=log12#

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