How do you condense $2 log 3 + 3 log 2 - log 6$ $2log3 +3log2 - log6$ ?

Question

How do you condense $2 log 3 + 3 log 2 - log 6$ $2log3 +3log2 - log6$ ?

1 Answer

Impact of this question

24480 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-27T05:51:48

It is $log 12$ $log12$

Explanation:

It is

$2 log 3 + 3 log 2 - log 6 = {log 3}^{2} + {log 2}^{3} - log 6 = log (3^{2} \cdot 2^{3}) - log 6 = log 72 - log 6 = log (\frac{72}{6}) = log 12$ $2log3 +3log2 - log6=log3^2+log2^3-log6= log(3^2*2^3)-log6=log72-log6=log(72/6)=log12$

Science

Math

Humanities

... and beyond

How do you condense $2 log 3 + 3 log 2 - log 6$ $2log3 +3log2 - log6$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you condense 2log3+3log2−log62log3 +3log2 - log6?

1 Answer

Explanation:

Related questions

Impact of this question

How do you condense $2 log 3 + 3 log 2 - log 6$ $2log3 +3log2 - log6$ ?