How do you simplify $log_2 5 + log_2 x - log_2 10$ ?

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Answer 1 · 2016-05-28T09:56:44

$log_2 x-1$

$log_2 5+log_2 x-log_2 10=log_2(5timesx/10)=log_2(x/2)$
but $log_2(x/2)=log_2x-log_2 2=log_2 x-1$

How do you simplify log_2 5 + log_2 x - log_2 10log_2 5 + log_2 x - log_2 10?