How do you solve $20^(x^2)=70$ ?

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Answer 1 · 2016-12-16T03:38:01

$x=+- 1.1909$

take log of both sides,

$log20^(x^2)=log70$
$x^2log20=log70$
$x^2=log70/log20=1.418182....$
$x=+-1.1909$ (4 decimal place)

How do you solve 20^(x^2)=7020^(x^2)=70?