How do you condense $(\frac{1}{2}) log (x + 7)$ $(1/2) log(x+7)$ ?

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How do you condense $(\frac{1}{2}) log (x + 7)$ $(1/2) log(x+7)$ ?

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Answer 1 · 2017-06-05T20:38:14

${log (x + 7)}^{\frac{1}{2}}$ $log(x+7)^(1/2)$

Explanation:

$using the law of logarithms$ $"using the "color(blue)"law of logarithms"$

$∙ {log x}^{n} \Leftrightarrow n log x$ $• logx^nhArrnlogx$

$\Rightarrow \frac{1}{2} log (x + 7) = {log (x + 7)}^{\frac{1}{2}} = log (\sqrt{x + 7})$ $rArr1/2log(x+7)=log(x+7)^(1/2)=log(sqrt(x+7))$

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