How do you use the properties of logarithms to expand $log_5 (5/x)$ ?

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Answer 1 · 2017-03-09T18:32:02

$log_5 (5/x)=log_5 5-log_5 x=1-log_5 x$

$log_5 (5/x)=log_5 5-log_5 x$ --> Use the property $log_b (x/y)=log_bx/log_b y$

$=1-log_5x$ ---> Use property $log_a a =1$

How do you use the properties of logarithms to expand log_5 (5/x)log_5 (5/x)?