How do you solve $ln(e^(7x)) = 15$ ?

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Answer 1 · 2018-03-02T18:44:01

$x=15/7$

This is for natural logarithms.

$ln(e^(7x))=15$

$ln(a^b)=bln(a)$

Then:

$ln(e^(7x))=15$

$7xln(e)=15$

$ln(e)=1$ ( The logarithm of the base is always 1 )

$7x=15=>x=15/7$

How do you solve ln(e^(7x)) = 15 ln(e^(7x)) = 15 ?