How do you evaluate $log_2 (0.25)$ ?

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Answer 1 · 2016-03-22T21:04:51

$log_2(0.25)$ $=-2$

$log_2(0.25)$

$=log_2(1/4)$

$=log_2 (1/2^2)$

$=log_2 2^-2$ ->use property $x^-n=1/x^n$

$=-2log_2 2$ -> use property $log_bx^n=nlog_bx$

$=-2 (1)$ -> use property $log_b b=1$

$=-2$

How do you evaluate log_2 (0.25)log_2 (0.25)?