How do you condense 2log_3 (x) + 5 log_3 (y) - 4log_3 (z)?

1 Answer
Bdub
Mar 22, 2016

2log_3 x +5 log _3 y - 4 log _3 z=log((x^2y^5)/(z^4))

Explanation:

2log_3 x +5 log _3 y - 4 log _3 z
=log_3 x^2 + log_3 y^5-log_3 z^4-> use propertieslog_b(xy)=log_b x+log_by and log_b(x/y) =log_b x-log_b y
=log((x^2y^5)/(z^4))

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