Question

How do you solve `log_b(x+2)-log_b4=log_b3x`?

Answer 1

`x=2/11`

Explanation:

`log_b (x+2)-log_b 4=log_b 3x`

`hArrlog_b ((x+2)/4)=log_b 3x`

or `(x+2)/4=3x`

or `x+2=12x`

or `11x=2` i.e. `x=2/11`