How do you condense $6log_3 u + 6log_3 v$ ?

Question

2804 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-16T12:08:26

$log_3 (uv)^6$

If logs are being added, then the numbers are multiplied.

$6log_3 u + 6log_3 v$

= $log_3 u^6 + log_3 v^6$

= $log_3 (u^6 xx v^6)$

= $log_3 (uv)^6$

How do you condense 6log_3 u + 6log_3 v 6log_3 u + 6log_3 v ?