How do you solve the equation $0.25=log 16^x$ ?

Question

4929 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-27T20:43:51

$x=0.208$

$0.25 = log16^x$

$loga^b=bloga therefore$

$0.25=xlog16$

$x=0.25/log16=0.208$

How do you solve the equation 0.25=log 16^x0.25=log 16^x?