How do you condense $log 40 - log 4$ $log 40 - log 4$ ?

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Answer 1 · 2018-05-11T13:29:13

$log 40 - log 4$ $log40-log4$ = $log (\frac{40}{4})$ $log(40/4)$ = $log 10 = 1$ $log10 = 1$

Use the quotient property of logarithms,
${log}_{b} (x) - {log}_{b} (y)$ $log_b(x)-log_b(y)$ = ${log}_{b} (\frac{x}{y})$ $log_b(x/y)$

$log 40 - log 4$ $log40-log4$ = $log (\frac{40}{4})$ $log(40/4)$ = $log 10 = 1$ $log10 = 1$

Note:
${log}_{b} (b) = 1$ $log_b(b)=1$ ---> hence ${log}_{10} (10) = 1$ $log_10(10) = 1$

How do you condense log 40 - log 4 log40−log4log 40 - log 4 ?