How do you condense $log (3 x + 7) - log x$ $log(3x + 7) - log x$ ?

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How do you condense $log (3 x + 7) - log x$ $log(3x + 7) - log x$ ?

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Answer 1 · 2016-03-22T19:10:06

$log (3 x + 7) - log x$ $log(3x+7)-logx$ $= log (\frac{3 x + 7}{x})$ $=log((3x+7)/(x))$

Explanation:

$log (3 x + 7) - log x$ $log(3x+7)-logx$
$= log (\frac{3 x + 7}{x})$ $=log((3x+7)/(x))$ -> use property ${log}_{b} x - {log}_{b} y = {log}_{b} (\frac{x}{y})$ $log_bx-log_by = log_b (x/y)$

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How do you condense $log (3 x + 7) - log x$ $log(3x + 7) - log x$ ?

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