How do you condense $2 log 7 + log 3$ $2 log 7 + log 3$ ?

Question

2353 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-15T07:15:04

$2 log 7 + log 3 = log 147$ $2log7+log3=log147$

$2 log 7 + log 3$ $2log7+log3$

= ${log 7}^{2} + log 3$ $log7^2+log3$

= $log 49 + log 3$ $log49+log3$

= #log(49xx3)$

= $log 147$ $log147$

How do you condense 2 log 7 + log 32log7+log32 log 7 + log 3?