Question

How do you evaluate `log_3 3root4 [3]`?

Answer 1

I found `5/4`

Explanation:

If I got the idea right I would write it as:
`log_3(3*3^(1/4))=log_3(3^(1+1/4))=log_3(3^(5/4))=5/4`
using the definition of log:
`log_ab=x ->a^x=b`