How do you use the properties of logarithms to expand $ln (6/sqrt(x^2+1))$ ?

Question

2767 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-25T15:00:36

$ln6-1/2ln(x^2+1)$

Expand $ln(6/(sqrt(x^2+1)))$

Rewrite the square root as an exponent.

$ln(6/(x^2+1)^(1/2))$

Use the log property $log(a/b)=loga - logb$

$ln6-ln(x^2+1)^(1/2)$

Use the log property $loga^b=bloga$

$ln6-1/2ln(x^2+1)$

How do you use the properties of logarithms to expand ln (6/sqrt(x^2+1))ln (6/sqrt(x^2+1))?