How do you use the properties of logarithms to expand ln (6/sqrt(x^2+1))ln(6x2+1)?

1 Answer
May 25, 2017

ln6-1/2ln(x^2+1)ln612ln(x2+1)

Explanation:

Expand ln(6/(sqrt(x^2+1)))ln(6x2+1)

Rewrite the square root as an exponent.

ln(6/(x^2+1)^(1/2))ln(6(x2+1)12)

Use the log property log(a/b)=loga - logblog(ab)=logalogb

ln6-ln(x^2+1)^(1/2)ln6ln(x2+1)12

Use the log property loga^b=blogalogab=bloga

ln6-1/2ln(x^2+1)ln612ln(x2+1)