How do you condense ln2+2ln3-ln18ln2+2ln3−ln18?
1 Answer
Jan 15, 2016
0
Explanation:
Using the 'laws of logarithms ' :
• logx + logy = logxy
• logx - logy =
log(x/y )log(xy) •
logx^n = n logx logxn=nlogx Applying these to this question :
ln2 + 2ln3 - ln18 = ln2 + ln3^2 -ln18 = ln2 + ln9 - ln18 ln2+2ln3−ln18=ln2+ln32−ln18=ln2+ln9−ln18
= ln((2xx9)/18) = ln(18/18) = ln1 =0=ln(2×918)=ln(1818)=ln1=0
