How do you evaluate $log_4 80 - log_4 5$ ?

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Answer 1 · 2016-05-28T08:50:51

$log _4 80-log_4 5=2$

$log _4 80-log_4 5=log _4 (80/5)$

$log _4 80-log_4 5=log_4 16$

$log _4 80-log_4 5=log_4 4^2$

$log _4 80-log_4 5=2*log_4 4$

$log_4 4=1$

$log _4 80-log_4 5=2*1$

$log _4 80-log_4 5=2$

How do you evaluate log_4 80 - log_4 5log_4 80 - log_4 5?