How do you condense $2 ln x + 3 ln y - 6 ln z$ ?

Question

5852 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-29T18:47:09

$ln((x^2y^3)/z^6)$

Laws/Properties of logarithms:

$log_am^n=nlog_am$

$log_a(m/n)=log_am-log_an$

$log_amn=log_am+log_an$

Condensing the expression:

$lnx^2+lny^3-lnz^6$

$lnx^2y^3-lnz^6$

$ln((x^2y^3)/z^6)$

How do you condense 2 ln x + 3 ln y - 6 ln z2 ln x + 3 ln y - 6 ln z?