How do you express ${log}_{4} {(1.6)}^{2}$ $log_4 (1.6)^2$ in terms of common logarithms?

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How do you express ${log}_{4} {(1.6)}^{2}$ $log_4 (1.6)^2$ in terms of common logarithms?

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Answer 1 · 2016-11-17T22:49:22

${log}_{4} {(1.6)}^{2} = 2 \frac{{log}_{10} (1.6)}{{log}_{10} (4)} = 2 \frac{ln (1.6)}{ln (4)}$ $log_4(1.6)^2 = 2log_10(1.6)/log_10(4) = 2ln(1.6)/ln(4)$

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How do you express ${log}_{4} {(1.6)}^{2}$ $log_4 (1.6)^2$ in terms of common logarithms?

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How do you express ${log}_{4} {(1.6)}^{2}$ $log_4 (1.6)^2$ in terms of common logarithms?