How do you solve $3^(x-2)=13^(4x)$ ?

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Answer 1 · 2016-02-05T19:00:46

Take natural logarithm both side

$ln(3^(x-2))=ln(13^(4x))$

$xln(3)-2ln(3) = 4xln(13)$

$2ln(3)=xln(3)-4xln(13)$

$2ln(3)=x(ln(3)-4ln(13))$

$(2ln(3))/(ln(3)-4ln(13)) = x$

How do you solve 3^(x-2)=13^(4x)3^(x-2)=13^(4x)?