How do you solve ${3.1}^{a - 3} = 9.42$ $3.1^(a-3)=9.42$ ?

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Answer 1 · 2016-10-21T12:15:23

$a = 4.9824$ $a=4.9824$

As ${3.1}^{a - 3} = 9.42$ $3.1^(a-3)=9.42$ , taking logarithm of both sides to base $10$ $10$ , we get

$(a - 3) \times log 3.1 = log 9.42$ $(a-3)xxlog3.1=log9.42$ and

$(a - 3) = \frac{log 9.42}{log 3.1} = \frac{0.97405}{0.49136} = 1.9824$ $(a-3)=log9.42/log3.1=0.97405/0.49136=1.9824$

and $a = 1.9824 + 3 = 4.9824$ $a=1.9824+3=4.9824$

How do you solve 3.1a−3=9.423.1^(a-3)=9.42?