Question

How do you condense `log4+ log2-log5`?

Answer 1

`log(8/5)`

Explanation:

Using the following `color(blue)"laws of logarithms"`

`•logx+logyhArrlog(xy)........(1)`

`•logx-logyhArrlog(x/y)........(2)`

using (1) : `log4+log2=log(4xx2)=log8`

using (2) : `log8-log5=log(8/5)`

`rArrlog4+log2-log5=log(8/5)`