How do you simplify $log_8 16 + log_8 256$ ?

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Answer 1 · 2016-06-20T09:22:23

Giving approximate answer of $4.004$ to 3 decimal places as a value

Simplified form $->log_8(4128)$

The addition of logs represents multiplication of the source numbers

$log_8(16)+log_8(256)" " =" " log_8(16xx258)" "=" "log_8(4128)$

Converting log base 8 to log base 10

$log_10(4128)/log_10(8) ~~4.0037$

Giving approximate answer of $4.004$ to 3 decimal places

How do you simplify log_8 16 + log_8 256log_8 16 + log_8 256?