How do you solve #log_9(-11x+2)=log_9(x^2+30)#?

1 Answer
Jim G.
Mar 7, 2018

#x=-4" or "x=-7#

Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_b x=log_b yrArrx=y#

#rArrx^2+30=-11x+2#

#"express in "color(blue)"standard form"#

#rArrx^2+11x+28=0larrcolor(blue)"in standard form"#

#rArr(x+4)(x+7)=0#

#x=4=0rArrx=-4#

#x+7=0rArrx=-7#

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