How do you calculate $log_(1/6) 216$ ?

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Answer 1 · 2016-05-04T14:27:44

Use the change of base rule $log_an = logn/loga$

$= log216/log(1/6)$

$= log(6^3)/log(6^-1)$

Use the rule $loga^n = nloga$

$= (3log6)/(-1log6)$

$= -3$

Hopefully this helps!

How do you calculate log_(1/6) 216log_(1/6) 216?