How do you solve $2log_7 (-2r)=0$ ?

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Answer 1 · 2016-09-14T10:15:30

$rArr r=-1/2$ .

By Defn., $log_ba=m iff b^m=a$ .

$;. 2log_7(-2r)=0$

$rArr log_7(-2r)=0$

$rArr 7^0=-2r$

$rArr 1=-2r$

$rArr r=-1/2$ .

How do you solve 2log_7 (-2r)=02log_7 (-2r)=0?