How do you evaluate $2 log_3 12 - 2 log_3 4$ ?

Question

1904 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-05T14:39:11

I found: $2$

I would use the properties of logs and write:

$log_3(12)^color(red)(2)-log_3(4)^color(red)(2)=$

and then:

$=log_3(12/4)^2=log_3(3^2)=2$

How do you evaluate 2 log_3 12 - 2 log_3 42 log_3 12 - 2 log_3 4?