How do you calculate log_(1/2) (15)?

1 Answer
Sep 16, 2016

log_(1/2)(15)=-3.9073

Explanation:

Let log_(1/2)(15)=y

Hence (1/2)^y=15. Now taking logarithm om both sides, we get

ylog(1/2)=log15

or

y=log15/log0.5

= 1.1761/(-0.3010

= -3.9073