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Question #32c44

1 Answer

Mar 9, 2017

B. $= {log}_{10} (x^{4} {(x - 6)}^{3})$ $=log_10 (x^4(x-6)^3)$

Explanation:

Use the properties

${log}_{b} x^{n} = n {log}_{b} x$ $log_bx^n=n log_bx$ and ${log}_{b} (x y) = {log}_{b} x + {log}_{b} y$ $log_b(xy)=log_b x+log_b y$

Therefore

$4 {log}_{10} x + 3 {log}_{10} (x - 6) = {log}_{10} x^{4} + {log}_{10} {(x - 6)}^{3}$ $4log_10 x + 3 log _10 (x-6)=log_10x^4+log_10(x-6)^3$

$= {log}_{10} (x^{4} {(x - 6)}^{3})$ $=log_10 (x^4(x-6)^3)$

$:.$ B

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